My claim and supporting evidence in short:
1) THE INFRARED CATASTROPHE (my words): Nitrogen (N2) and oxygen (O2) - 99% of the dry atmosphere - are assumed non-greenhouse gases (non-GHGs) and are a key premise in greenhouse theory (GH) as they do not, unlike the GHGs, absorb or emit infrared (IR) radiation. I claim this premise is a contradiction to both Quantum Mechanics (QM) and Thermodynamics (TD); where all matter - above absolute 0 Kelvin - radiates and interacts with infrared radiation (IR).
2) I claim - and can prove - the GHGs (CO2, methane -CH4, H20, and others) have been mistakenly interpreted, and are really only the thermo-electric (TE) gases, measured or detected by (early 19th Century technology) thermo-electric transducers (thermopiles and the like).
3) Quantum Mechanics reveals O2 and N2 also have vibrational frequencies (at wavenumbers 1556cm-1 and 2338cm-1 respectively) in the infrared range of the electromagnetic spectrum (EMS) , but as they have no electric dipole moment they are not thermo-electric frequencies: they do not generate electricity and so are not detected by IR (TE) detectors (2). To detect and measure these - and CO2's 1338cm, all of H2O's, and CH4's 2 (non-GHG) frequencies - the 20th Century instrument 'Raman Laser Spectrometer' is required. Raman Spectrometer is the complementary instrument to IR (TE) spectroscopy and is widely used (by NASA, NOAA, and able to be used in the measurement of GHG concentrations!!) and is understood by all chemists and physicists.
4) As supporting experimental evidence to my claim, the report: Field Tests of a Laser Raman Measurement System for Aircraft Engine Exhaust Emissions reveals how N2's, O2's and CO2's temperature and constituent quantity are measured by Raman at the said frequencies, and are found to be equivalent! to IR (TE) measurements.
5) I claim the QM theory behind, and application of, the CO2 laser is evidence N2 emits and absorbs IR at the said frequencies. N2 absorbs when radiated (heated) by IR 'light'; and would not operate is it did not so. Here N2 is said to be 'metastable' (long lasting absorption) and is radiated by electrons to excite (heat) its 2338cm frequency to excite (heat!) CO2's close 2349cm frequency.
6) I conclude all gases in the atmosphere are GHGs; there are no special heat radiating/non radiating ones; they are only different by their respective heat capacities. There has been an oversight, followed by misconception, followed by massive extrapolation.
7) From my research I have discovered and hypothesis: black body radiation theory (black body spectrum) is outdated, and is incomplete due to its reliance and foundation upon 19th Century thermo-electrics only (as above). It has lead to contradictions and paradoxes revealed in the term emissivity.
It is true that there is a nonzero absorption cross section in the IR for diatomic molecules but this is a second order (Raman) process that involves virtual excitation of electronic states. There are simply no transitions that can be involved in IR absorption. The standard undergraduate explanation is that diatomic molecules don't have a dipole moment so the low-lying vibrational and rotational modes aren't excited by photons. You need an intermediate excited state which makes the cross section very small. On the other hand gases like H2O, CO2 , CH4 etc have dipole moments along their bonds and their rotational and vibrational states can be excited by photons, this is why they absorb in the IR. Considering the amount of spectroscopic data available for these gases I would say that all of this physics is unambiguous and you'd have to be looney to claim that all previous experiments and theory are incorrect.
So as far as I can tell the only remaining possible claim is that for kinematic reasons diatomic molecules can contribute significantly to warming despite the small cross section for Raman processes. Is that what you're claiming Blair?
With your example, if you radiate N2 and O2 with IR light, yes there will be absorption due to coupling with the electric quadrupole moment of the radiation. However the number of molecules that can be excited will be very small, since there is no dipole absorption (dipole transitions are forbidden by conservation of parity). This experiment has probably been done before. Do you have access to physics journals? I can try to find an article for you.
What matters in the atmosphere is the absorption cross section since it determines how transparent N2 and O2 are to IR radiation. I suspect that the corresponding optical depth may be dozens of kilometres, because Planck's constant is very small and the speed of light is very large. If that is the case then N2 and O2 will not be absorbers in the IR. On the other hand heteronuclear molecules will have dipole moments along their bonds so they can absorb dipole radiation and that is why they are opaque to IR radiation. Have you done this calculation? You need to know the multipole components of electromagnetic radiation in the atmosphere and the matrix elements of the transitions.
The lesson here, in your language I guess, is that spectroscopy does not just depend on the frequency of the transitions but also the probability of the transition, which can be strongly suppressed by factors of Planck's constant and the speed of light when you are looking at multipole transitions. By the way this has nothing to do with Raman.
I've tried to help you here by pointing out what is standard and known at the undergraduate level for an understanding of quantum mechanics and molecular transitions. If you're genuinely concerned that you've made a huge discovery that'll upset science or whatever, then you won't get anywhere unless you convince people to listen. Maybe your ideas have some merit, maybe they don't. But so far you've provided me with a prediction of your theory which is trivial and it appears that it's well studied.
Can you provide me with an experimental prediction that is not already known and would violate common intuition or textbook theory? If you can produce a prediction, perhaps you could ask some experimentalists to verify it and collect your Nobel prize or whatever.
exhaust of a T53-L13A gas turbine engine with a new field portable instrument
devised specifically for gas turbine exhaust emission measurements. The gas
turbine exhaust was analyzed by conventional instruments for CO, CO 2 , NO, NO x ,
total hydrocarbons, smoke and temperature, and these data were used as a
"calibration" standard for the evaluation of the laser Raman instrument. Results
thus far indicate good correlations for CO 2 , O 2 , smoke, hydrocarbons and
temperature. The instrument was not sensitive enough for NO detection but the
data analysis indicates that 100 ppm may be detectable with instrument improve-
ments. CO analysis was not attempted, but it is expected that CO could be
detected with further research. NO;; (or NOx) was not attempted because
theoretical and expeiimental laboratory analysis indicated severe lalt rierc.i^e
with CO Z . The most severe problem area was laser induced hydrocarbon
fluorescence when the exhaust contained large total hydrocarbon concentrations.
The overall conclusion was that the laser Raman method shows a good potential
for aircraft gas turbine emission analysis.
I've already told you, this is an extremely well known fact that is taught to undergraduates. N2 and O2 have electric quadrupole transitions. No one is saying they don't. You don't need to keep repeating this to people as if it's some fundamental new discovery.
You've told me that the grand prediction of your theory is that if you radiate O2 and N2 with certain frequencies in the IR range, they will heat up. Yes, they will. We know that. You don't have to keep yelling. All this is known. If you use google you could probably find several lecture notes that go through this. They could probably also ask you to calculate the cross section for the direct quadrupole transition, for Raman, etc, etc. A slightly harder task- and one that I wouldn't be able to do in my head - is to calculate the spectral weight of the absorption line for the atmosphere. However, it can be done and if you had the proper training in physics you could possibly do that calculation yourself and hopefully it should agree with the textbook. If it doesn't agree, then I'd say there is a huge probability of error on your part. This is basic physics, yes it may be interesting to some people like yourself, but it is all very well known, I assure you. You would not be able to have a career doing quantum mechanics without knowing this stuff.
I am confident that your work will pass peer review, since you seem to be much more qualified than people who have earned doctorates and work professionally as researchers in quantum mechanics. After the publication of your groundbreaking research, I am sure you will be approached by several publishers to author a textbook on the basics of quantum mechanics, since all the current ones are wrong.
I wish you the best of luck.
means they do not absorb or emit radiation on
transitions within the same electronic state. They
may have very weak quadrupole transitions.
The molecules N2 and O2, which represent the major
constituents of our atmosphere, cannot absorb the infrared
radiation emitted by the earth. Other molecules,
such as CO2, H2O, NH3 and CH4 do have an electric
dipole moment and absorb infrared radiation on their
numerous vibrational-rotational transitions. Although
they are present in our atmosphere only in small concentrations
they can seriously perturb the delicate energy
balance between absorbed incident sun radiation and
the energy radiated back into space by the earth (greenhouse
effect). If their concentration is increased by only
small amounts this can increase the temperature of the
atmosphere at the earth’s surface (greenhouse effect)"