Ingham 29: "If your (unpublished, unreviewed) "research" is as coherent as your explanation of it, it's truly a shame that you'd throw your life away on such a waste of time. Go get a science degree then contribute something useful mate. Then again that might make you one of the "establishment" that is trying to cover up the "IR catastrophe" I guess ay"
Lee:30,31 "Well as a humble theoretical physicist It's my job to take all claims seriously if they could potentially have some merit. We know that CO2 is a greenhouse gas since there's overwhelming evidence for it, but it looks like Blair is claiming that N2 and O2 are also greenhouse gases...;Considering the amount of spectroscopic data available for these gases I would say that all of this physics is unambiguous and you'd have to be looney to claim that all previous experiments and theory are incorrect...."
Macdonald 50: "You're busted and running. Bye."
My claim and supporting evidence in short:
1) THE INFRARED CATASTROPHE (my words): Nitrogen (N2) and oxygen (O2) - 99% of the dry atmosphere - are assumed non-greenhouse gases (non-GHGs) and are a key premise in greenhouse theory (GH) as they do not, unlike the GHGs, absorb or emit infrared (IR) radiation. I claim this premise is a contradiction to both Quantum Mechanics (QM) and Thermodynamics (TD); where all matter - above absolute 0 Kelvin - radiates and interacts with infrared radiation (IR).
2) I claim - and can prove - the GHGs (CO2, methane -CH4, H20, and others) have been mistakenly interpreted, and are really only the thermo-electric (TE) gases, measured or detected by (early 19th Century technology) thermo-electric transducers (thermopiles and the like).
3) Quantum Mechanics reveals O2 and N2 also have vibrational frequencies (at wavenumbers 1556cm-1 and 2338cm-1 respectively) in the infrared range of the electromagnetic spectrum (EMS) , but as they have no electric dipole moment they are not thermo-electric frequencies: they do not generate electricity and so are not detected by IR (TE) detectors (2). To detect and measure these - and CO2's 1338cm, all of H2O's, and CH4's 2 (non-GHG) frequencies - the 20th Century instrument 'Raman Laser Spectrometer' is required. Raman Spectrometer is the complementary instrument to IR (TE) spectroscopy and is widely used (by NASA, NOAA, and able to be used in the measurement of GHG concentrations!!) and is understood by all chemists and physicists.
4) As supporting experimental evidence to my claim, the report: Field Tests of a Laser Raman Measurement System for Aircraft Engine Exhaust Emissions reveals how N2's, O2's and CO2's temperature and constituent quantity are measured by Raman at the said frequencies, and are found to be equivalent! to IR (TE) measurements.
5) I claim the QM theory behind, and application of, the CO2 laser is evidence N2 emits and absorbs IR at the said frequencies. N2 absorbs when radiated (heated) by IR 'light'; and would not operate is it did not so. Here N2 is said to be 'metastable' (long lasting absorption) and is radiated by electrons to excite (heat) its 2338cm frequency to excite (heat!) CO2's close 2349cm frequency.
6) I conclude all gases in the atmosphere are GHGs; there are no special heat radiating/non radiating ones; they are only different by their respective heat capacities. There has been an oversight, followed by misconception, followed by massive extrapolation.
7) From my research I have discovered and hypothesis: black body radiation theory (black body spectrum) is outdated, and is incomplete due to its reliance and foundation upon 19th Century thermo-electrics only (as above). It has lead to contradictions and paradoxes revealed in the term emissivity.
1Blair Macdonald I
wonder if Albert Einstein knew almost all the
atmosphere defies quantum mechanics and thermodynamics in that it does not emit
or absorb any IR radiation (AKA heat), at any temperature! - making it the only
matter in the universe (save dark matter and dark energy) to not interact with
light. The only saving grace is are the whinny whinny tinny, but very spicy
CO2! It does all the work. Yet where the shadow of the eclipse falls, so does
the temperature (but no radiation). What gives? I think we are still in the
'dark ages'
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2Blair Macdonald And
I have the answer.
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3Tom Rodolfo Lee considering
Albert Einstein published work on Rayleigh scattering in the atmosphere, yeah
I'd say he knew CO2 absorbs in the IR..
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4Blair Macdonald Tom
Rodolfo Lee Well he, and all he was standing on - Stephan, Boltzmann etc -,
made a mistake; or better said, what they did was incomplete and is outdated in
the modern world.
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5Julian Ingham "almost all the atmosphere doesn't interact
with light" wtf are you on about mate? It does interact with light but as
any kindergartener could tell you in a theory of electromagnetism and
nonrelativistic scalars all interactions are irrelevant operators. This doesn't
defy quantum mechanics it is a basic manifestation of it and the reason why the
sky is blue (e.g. page 114 http://mcgreevy.physics.ucsd.edu/s15/215C-2015-lectures.pdf)
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6Tom Rodolfo Lee lel
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7Samuel Lee Julian Ingham Electromagnetism is the
biggest scientific fraud since Piltdown man
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8Julian Ingham Low
energy Ken Wilson requires requires physical quantities to be insensitive to UV
physics. I know more about UV physics than the generals, believe me.
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9Blair Macdonald Julian
Ingham IR photons are assumed not to interact with N2 and O2 which is (like I
said) basically the total atmosphere. That is current greenhouse theory, and it
is wrong.
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10Blair Macdonald I
don't understand any of this "Low energy Ken Wilson requires requires
physical quantities to be insensitive to UV physics. I know more about UV
physics than the generals, believe me." Ken Wilson ? 'generals'
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11Blair Macdonald Samuel
Lee and Julian "Electromagnetism is the biggest scientific fraud since
Piltdown man"; what fallacy is that? Straw-man? What if I could show N2
and O2 have vibrational modes in the IR range of the EMS and detect them, and
show they are used practically- would that be the discovery of the Century?
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12Julian Ingham Blair
the low energy and piltdown man comments weren't directed at you they were
jokes about Trump/Stephen Crothers (a crackpot "physicist"). As for
what silly comments you make, you need to google "Rayleigh
scattering" -- whilst photons DO interact with atoms in the atmosphere,
scattering is dominant in the UV. This is a calculation one can easily arrive
at classically (get a copy of Jacksons electromagnetism out from your local
library) or quantum mechanically using Wilsonian effective field theory (see my
link above)
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13Tom Rodolfo Lee popcorn
time
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14Blair Macdonald Julian
Ingham IR is my business, I am solving the IR catastrophe, not the UV and I am
playing with you, just for fun; testing my theory is water tight . IR: N2 and
O2 you read up on Shrodinger predicted vibrational modes for N2 and O2 in the
IR of the EMS. You'll see them at 2338cm and 1388cm respectively . Then
learn about the Raman laser IR spectroscopy (not the atmospheric Raman effect,
I'm good with that, and not Rayleigh). Who's Trump? Stephen??
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15Julian Ingham Blair
mate again haha you misunderstood the UV joke -- I was calling Ken Wilson
"low energy" both in reference to the fact effective theory only
makes low energy predictions and in reference to Donald Trumps jibe at Jeb
Bush...UV physics is nonuniversal so isn't predicted by effective theory that's
what I was joking about just never mind haahaha Samuel Lee lmao
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16Julian Ingham I
really don't understand what your problem with basic quantum mechanics is. Do
you have a problem with the concept of Rayleigh scattering or not? If not then
you appreciate that scattering of light by atoms favours high frequencies and
that is why the sky is blue (most of the light the sky reflects is bluer
because blue light has a higher frequency than red light)
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17Julian Ingham like
are you trying to say that raman scattering due to the vibrational modes of
molecules means rayleigh scattering is a poor model for the interaction of
light with the atmosphere? i suppose it depends on what observables you're
talking about but like.....you realise that inelastic scattering is typically
much much weaker than elastic scattering?? that's kind of like the main
experimental hurdle with doing raman spectroscopy in general bro
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18Tom Rodolfo Lee I
don't know if Raman scattering is that small in the atmosphere, the excitation
energies for rotational modes in diatomic molecules is typically 10meV or so
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19Julian Ingham It's
smaller than Rayleigh scattering though haha
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20Blair Macdonald Julian
Ingham "Julian Ingham IR is my business, I am solving the IR catastrophe,
not the UV and I am playing with you, just for fun; testing my theory is water
tight . IR: N2 and O2 you read up on Shrodinger predicted vibrational modes for
N2 and O2 in the IR of the EMS. You'll see them at 2338cm and 1388cm
respectively . Then learn about the Raman laser IR spectroscopy (not the
atmospheric Raman effect, I'm good with that, and not Rayleigh). "
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21Blair Macdonald Tom
Rodolfo Lee I said I am good with Raman and Rayleigh effects; its 'IR' Raman
spectroscopy : watch and learn. It reveals N2 and O2s modes. They are
greenhouse gases. https://www.youtube.com/watch?v=TMLnUmbLwUI&t=433s

Vibrational Spectroscopy: IR vs. Raman
Inorganic
Chemistry: Tutorial 1…
YOUTUBE.COM
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22Tom Rodolfo Lee What's
the IR "catastrophe"? And where is this research published?
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23Paul Enviro Solar Samuel
Lee electromagnetism accounts for all chemistry and biology. Life itself must
be the fraud. A basic electrical engine doesn't function without applying the
principals. There would be no technological or mechanical advances without it.
If its a fraud stay well away from your car.
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24Blair Macdonald It
is my work, I am currently writing. It is my words, my name. It is what I have
been saying/claiming: there is a contradiction to QM and TDs IR N2 and O2 (the
atmosphere) and I offer a solution. It focuses on the non GHGs and why they are
nonGHGs. There's been a mistake or oversight.
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25Paul Enviro Solar Blair
Macdonald http://www.sciencescene.com/.../The%20Green%20House... Basic
stuff how do you think you experience differences in temperature if the
atmosphere doesn't absorb heat?
The Green house effect
The
greenhouse effect is the process in which the emission of infrared radiation by
the…
SCIENCESCENE.COM
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26Paul Enviro Solar http://www.engineeringtoolbox.com/specific-heat-capacity...

Specific Heat and Individual Gas Constant
of Gases
Specific
heat at constant volume, specific…
ENGINEERINGTOOLBOX.COM
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27Paul Enviro Solar All
molecules absorb heat at difference rates. None of our sciences technologies or
measurements would be possible without accurate known properties or ranges for
this effect.
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28Julian Ingham Mate
you're not playing with me you're sounding off a bunch of crap haha. Also I
know more than enough about Raman spectroscopy as my earlier comment indicated,
but you've offered zero explanation of how inelastic scattering of photons is
at all relevant to anything that invalidates climate science. No one assumes
inelastic scattering doesn't exist just that it is smaller than elastic
scattering.
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29Julian Ingham If
your (unpublished, unreviewed) "research" is as coherent as your
explanation of it, it's truly a shame that you'd throw your life away on such a
waste of time. Go get a science degree then contribute something useful mate.
Then again that might make you one of the "establishment" that is
trying to cover up the "IR catastrophe" I guess ay
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30Tom Rodolfo Lee Well as a humble theoretical physicist It's my job
to take all claims seriously if they could potentially have some merit. We know
that CO2 is a greenhouse gas since there's overwhelming evidence for it, but it
looks like Blair is claiming that N2 and O2 are also greenhouse gases...
It is true that there is a nonzero absorption cross section in the IR for diatomic molecules but this is a second order (Raman) process that involves virtual excitation of electronic states. There are simply no transitions that can be involved in IR absorption. The standard undergraduate explanation is that diatomic molecules don't have a dipole moment so the low-lying vibrational and rotational modes aren't excited by photons. You need an intermediate excited state which makes the cross section very small. On the other hand gases like H2O, CO2 , CH4 etc have dipole moments along their bonds and their rotational and vibrational states can be excited by photons, this is why they absorb in the IR. Considering the amount of spectroscopic data available for these gases I would say that all of this physics is unambiguous and you'd have to be looney to claim that all previous experiments and theory are incorrect.
So as far as I can tell the only remaining possible claim is that for kinematic reasons diatomic molecules can contribute significantly to warming despite the small cross section for Raman processes. Is that what you're claiming Blair?
It is true that there is a nonzero absorption cross section in the IR for diatomic molecules but this is a second order (Raman) process that involves virtual excitation of electronic states. There are simply no transitions that can be involved in IR absorption. The standard undergraduate explanation is that diatomic molecules don't have a dipole moment so the low-lying vibrational and rotational modes aren't excited by photons. You need an intermediate excited state which makes the cross section very small. On the other hand gases like H2O, CO2 , CH4 etc have dipole moments along their bonds and their rotational and vibrational states can be excited by photons, this is why they absorb in the IR. Considering the amount of spectroscopic data available for these gases I would say that all of this physics is unambiguous and you'd have to be looney to claim that all previous experiments and theory are incorrect.
So as far as I can tell the only remaining possible claim is that for kinematic reasons diatomic molecules can contribute significantly to warming despite the small cross section for Raman processes. Is that what you're claiming Blair?
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31Tom Rodolfo Lee If
that is the claim then I'd find it genuinely very interesting because it would
be a NAture or Science article and would contradict very basic intuition that
is taught in all physics training
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32Blair Macdonald Tom
Rodolfo Lee Okay, what I have deduced is: what we call IR spectroscopy should
be correctly termed thermo-electric (TE) spectroscopy from the fact they use
thermo-electric transducers - via the 1828 Seebeck Effect. Transducers being
the key word. This is what Tyndall used in 1859. From this the so called GHGs,
I deduce, should be are correctly termed the TE gases: as they really only
generate an Electro Motive Force (EMF), AKA electricity, from their 'dipoles'
(their ELECTRIC dipole moments). That is my claim. TE (thermopiles and the
like) are 19th Century technology; they do show the TE/IR modes, but they do
not show all as they were developed before QM, Raman effect, and the modern
laser. With QMs, Raman effect, and Lasers we now have Raman Spectroscopy: the
complement to IR (TE) spectroscopy (as shown in clip), and it reveals (with the
laser) the 'hidden' QM predicted modes of N2, O2, CH4, H2O, and CO2 (and more)
that are also in the IR range of the EMS that IR/TE spectroscopy does not. N2
at 2338cm and O2 at 1556 and CO2 at 1388. Remember, spectroscopy is the study
of light and its interaction with matter. QM predicts all the modes, and it
does too N2 and O2. If you wish; and I insist, I can show you, and prove to all
I am right by experiment and application of this QM knowledge (I would put my
life on it; actually we all do) ; but before I do, know that modern Raman
spectrometers can measure everything the IR/TE spectrometer can: temperature of
the molecule and quantity of gas, and they do this by measuring the excitation
of the molecule. Please do not lead me off on Red Hearings; if you want the
experiment (paper) let me know. Thank for your interest: that is science, and I
respect that. We need to find where I am wrong; because if this is right, this
will be the greatest upset in the history of science and I am not sure I want
that. Blair
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33Blair Macdonald Tom
Rodolfo Lee By the way; in my research I also learnt, to my shock and horror,
Stefan and Boltzmann used thermopiles in their black body theory: if I am
right, radiation theory will need reviewed and updated. The uncomfortable and
'arm waving' emissivity will go, and be explained as a correction for the TE
properties of a substance: with this I can explain the contradictions it
presents (shiny metals, and high values for water and snow for instance). But
please, one thing at a time.
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34Tom Rodolfo Lee Do
you have a concrete prediction? What is this "greatest upset in the
history of science" that you are referring to?
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35Blair Macdonald Prediction: I had to think for a moment. Yes: if N2
in isolation is radiated with IR light, its temperature will increase
proportional to its excitation. The same goes for O2 and for CO2s 1388! I can
show you an experiment where we can measure the temperature (the excitation) of
CO2 without and IR (TE) detectors, and the two (IR and Raman Laser) equivalent.
They upset: greenhouse theory. Our understanding of present, past and future
climate (and weather).
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36Tom Rodolfo Lee Blair what you are saying is not particularly
interesting or exciting. The interaction between matter and radiation is the
most well understood and accurate scientific theory of all time. It's the basis
for our most accurate atomic clocks.
With your example, if you radiate N2 and O2 with IR light, yes there will be absorption due to coupling with the electric quadrupole moment of the radiation. However the number of molecules that can be excited will be very small, since there is no dipole absorption (dipole transitions are forbidden by conservation of parity). This experiment has probably been done before. Do you have access to physics journals? I can try to find an article for you.
What matters in the atmosphere is the absorption cross section since it determines how transparent N2 and O2 are to IR radiation. I suspect that the corresponding optical depth may be dozens of kilometres, because Planck's constant is very small and the speed of light is very large. If that is the case then N2 and O2 will not be absorbers in the IR. On the other hand heteronuclear molecules will have dipole moments along their bonds so they can absorb dipole radiation and that is why they are opaque to IR radiation. Have you done this calculation? You need to know the multipole components of electromagnetic radiation in the atmosphere and the matrix elements of the transitions.
The lesson here, in your language I guess, is that spectroscopy does not just depend on the frequency of the transitions but also the probability of the transition, which can be strongly suppressed by factors of Planck's constant and the speed of light when you are looking at multipole transitions. By the way this has nothing to do with Raman.
With your example, if you radiate N2 and O2 with IR light, yes there will be absorption due to coupling with the electric quadrupole moment of the radiation. However the number of molecules that can be excited will be very small, since there is no dipole absorption (dipole transitions are forbidden by conservation of parity). This experiment has probably been done before. Do you have access to physics journals? I can try to find an article for you.
What matters in the atmosphere is the absorption cross section since it determines how transparent N2 and O2 are to IR radiation. I suspect that the corresponding optical depth may be dozens of kilometres, because Planck's constant is very small and the speed of light is very large. If that is the case then N2 and O2 will not be absorbers in the IR. On the other hand heteronuclear molecules will have dipole moments along their bonds so they can absorb dipole radiation and that is why they are opaque to IR radiation. Have you done this calculation? You need to know the multipole components of electromagnetic radiation in the atmosphere and the matrix elements of the transitions.
The lesson here, in your language I guess, is that spectroscopy does not just depend on the frequency of the transitions but also the probability of the transition, which can be strongly suppressed by factors of Planck's constant and the speed of light when you are looking at multipole transitions. By the way this has nothing to do with Raman.
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37Tom Rodolfo Lee I
just found some lecture notes from a quantum mechanics course that show that
indeed O2 has some absorption lines in the IR for atmospheric conditions but
the width of the lines is so small that the corresponding spectral weight is
negligible in comparison to the greenhouse gases. This is probably because of
the reasons I mentioned above.
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38Blair Macdonald Tom
Rodolfo Lee Tom, are you a Professor or PhD, or ? Just want to check who I am
working with.
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39Tom Rodolfo Lee Yes
I have a PhD in physics
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40Blair Macdonald You
say: " what (I) am saying is not particularly interesting or
exciting" The arrogance! I am only claiming GH theory is wrongly
neglecting N2 and O2 (and the other Raman Modes, CO2 mainly ) and have said
with them included (which I can prove, but have not yet done so) will collapse
the current standard model of the atmosphere - not interesting or exciting!
Then "The interaction between matter and radiation is the most well
understood and accurate scientific theory of all time. It's the basis for our
most accurate atomic clocks" Here you are committing logical fallacies;
(possibly straw-man, definitely red hearing, and possibly fallacy of
composition ) and you continue to do so with your other attempts of refuting my
claim. QM is not at all at risk; I am using QM to complete, or augment, our
understanding of the atmosphere. I am saying atmospheric theory needs updating.
You appear not to be acknowledging established theory, principles and
application in modern (Raman) spectroscopy which is based on QM and (its)
Laser. This is the right place (page) to talk about laser and QM. I will show
you my proof, but first do you agree N2, O2, and CO2 have (Raman Active) modes
at 2338, 1556 and 1388 cm-1 respectively. If yes, I will show you a proof by
application QM theory N2 Radiates; and then I will show you another, and one
other after that. By the way; some modes are both Raman and thermoelectric (in
H20 and CH4 and others). Please reply to yes or no. Sorry about the delays,
busy days just now.
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41Blair Macdonald https://www.youtube.com/watch?v=AhyEY0Ddwz4&t=11s... Here
is the application of thermo-electric transducers used in 'IR' cameras: not
detecting liquid nitrogen. The reason: there is no EMF produced by N2 and O2 at
any temperature. But this does not mean the shown N2 does not have a
temperature (above 0K). I look forward to your 'yes'.

Liquid Nitrogen Transparent on Thermal…
YOUTUBE.COM
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42Julian Ingham I
don't think you know what a strawman is mate hahaha saying we understand
optical physics well is definitely not one
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43Blair Macdonald Paul
Enviro Solar I think you misunderstand my theory; I turn it back on you: how do
you think you experience differences in temperature if the atmosphere doesn't
absorb heat - only 1 or 2 percent of it does? My answer is it does absorb and
emit: N2 and O2 are GHGs just as Fourier implied. N2 and O2 absorb and
emit in the IR range of the EMS. It was Tyndall who got us off track with his
experiment, N2 and O2 are not detected; but they are now by laser Raman. I
complete Fourier's work, after 200 odd years. Are you a PhD also?
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44Tom Rodolfo Lee If you're arguing that O2 and N2 have transitions in
the IR, well that is very well known. They're electric quadrupole transitions.
If you want to show that they lead to warming in the atmosphere then you need
to calculate the probability of absorption. There is no great mystery about why
O2 and N2 don't absorb IR in the atmosphere. It has nothing to do with Raman or
whatever, it's just that these processes are kinematically suppressed.
I've tried to help you here by pointing out what is standard and known at the undergraduate level for an understanding of quantum mechanics and molecular transitions. If you're genuinely concerned that you've made a huge discovery that'll upset science or whatever, then you won't get anywhere unless you convince people to listen. Maybe your ideas have some merit, maybe they don't. But so far you've provided me with a prediction of your theory which is trivial and it appears that it's well studied.
Can you provide me with an experimental prediction that is not already known and would violate common intuition or textbook theory? If you can produce a prediction, perhaps you could ask some experimentalists to verify it and collect your Nobel prize or whatever.
I've tried to help you here by pointing out what is standard and known at the undergraduate level for an understanding of quantum mechanics and molecular transitions. If you're genuinely concerned that you've made a huge discovery that'll upset science or whatever, then you won't get anywhere unless you convince people to listen. Maybe your ideas have some merit, maybe they don't. But so far you've provided me with a prediction of your theory which is trivial and it appears that it's well studied.
Can you provide me with an experimental prediction that is not already known and would violate common intuition or textbook theory? If you can produce a prediction, perhaps you could ask some experimentalists to verify it and collect your Nobel prize or whatever.
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45Blair Macdonald Paul
Enviro Solar On specific heat capacities: Yes, this is part of my proof, N2 and
O2 have SHCs and these values are determined by the vibrational behaviour of
the molecule. If they had no absorption or emit they would have a 0 SHC.
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46Blair Macdonald Tom
Rodolfo Lee In the Report 'FIELD TESTS OF A LASER RAMAN MEASURE- MENT SYSTEM
FOR AIRCRAFT ENGINE EXHAUST EMISSIONS' Raman Spectrometers are used measure
temperature, concentration (and more) of N2 O2 and CO2. Remember, Raman cannot
'see' IR, but as they explain, their measurement are equivalent (the same)
only they use the 1388 mode. They know all about the atmosphere by Raman
spectroscopy (RS) and this is why RS is the instrument of choice on solar
system space probes. I will try and message it to you as they have taken it
sadly down. Here is the abstract: Laser induced Raman and fluorescent
measurements were made in the
exhaust of a T53-L13A gas turbine engine with a new field portable instrument
devised specifically for gas turbine exhaust emission measurements. The gas
turbine exhaust was analyzed by conventional instruments for CO, CO 2 , NO, NO x ,
total hydrocarbons, smoke and temperature, and these data were used as a
"calibration" standard for the evaluation of the laser Raman instrument. Results
thus far indicate good correlations for CO 2 , O 2 , smoke, hydrocarbons and
temperature. The instrument was not sensitive enough for NO detection but the
data analysis indicates that 100 ppm may be detectable with instrument improve-
ments. CO analysis was not attempted, but it is expected that CO could be
detected with further research. NO;; (or NOx) was not attempted because
theoretical and expeiimental laboratory analysis indicated severe lalt rierc.i^e
with CO Z . The most severe problem area was laser induced hydrocarbon
fluorescence when the exhaust contained large total hydrocarbon concentrations.
The overall conclusion was that the laser Raman method shows a good potential
for aircraft gas turbine emission analysis.
exhaust of a T53-L13A gas turbine engine with a new field portable instrument
devised specifically for gas turbine exhaust emission measurements. The gas
turbine exhaust was analyzed by conventional instruments for CO, CO 2 , NO, NO x ,
total hydrocarbons, smoke and temperature, and these data were used as a
"calibration" standard for the evaluation of the laser Raman instrument. Results
thus far indicate good correlations for CO 2 , O 2 , smoke, hydrocarbons and
temperature. The instrument was not sensitive enough for NO detection but the
data analysis indicates that 100 ppm may be detectable with instrument improve-
ments. CO analysis was not attempted, but it is expected that CO could be
detected with further research. NO;; (or NOx) was not attempted because
theoretical and expeiimental laboratory analysis indicated severe lalt rierc.i^e
with CO Z . The most severe problem area was laser induced hydrocarbon
fluorescence when the exhaust contained large total hydrocarbon concentrations.
The overall conclusion was that the laser Raman method shows a good potential
for aircraft gas turbine emission analysis.
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47Blair Macdonald I
have to go out to tea now. Will be back with another independent proof: that N2
and or O2 in isolation emit and radiate at there said IR modes 2338 and 1556
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48Tom Rodolfo Lee I've
already said that N2 and O2 absorb in the IR, in a gas the probability of
absorption will be kinematically supressed. Do you disagree with that?
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49Tom Rodolfo Lee You
know what, never mind. All the best with your "theories."
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50Blair Macdonald You're
busted and running. Bye.
51Blair Macdonald Dr.
Lee before we go, my all time favourite, and what better place to share this
on Albert Einstein 's page, the laser.
The CO2 laser. Here N2 is radiated by electron at its 2338 mode !! and this
excites CO2's ('IR') 2349 mode!! Figure that. Nitrogen is said to be
metastable, it radiates for long 'time', and this is also knowledge used and
understood independently in astronomy.
52Tom Rodolfo Lee I
just don't understand why you keep telling me that N2 and O2 radiate and absorb
in the IR.
I've already told you, this is an extremely well known fact that is taught to undergraduates. N2 and O2 have electric quadrupole transitions. No one is saying they don't. You don't need to keep repeating this to people as if it's some fundamental new discovery.
You've told me that the grand prediction of your theory is that if you radiate O2 and N2 with certain frequencies in the IR range, they will heat up. Yes, they will. We know that. You don't have to keep yelling. All this is known. If you use google you could probably find several lecture notes that go through this. They could probably also ask you to calculate the cross section for the direct quadrupole transition, for Raman, etc, etc. A slightly harder task- and one that I wouldn't be able to do in my head - is to calculate the spectral weight of the absorption line for the atmosphere. However, it can be done and if you had the proper training in physics you could possibly do that calculation yourself and hopefully it should agree with the textbook. If it doesn't agree, then I'd say there is a huge probability of error on your part. This is basic physics, yes it may be interesting to some people like yourself, but it is all very well known, I assure you. You would not be able to have a career doing quantum mechanics without knowing this stuff.
I've already told you, this is an extremely well known fact that is taught to undergraduates. N2 and O2 have electric quadrupole transitions. No one is saying they don't. You don't need to keep repeating this to people as if it's some fundamental new discovery.
You've told me that the grand prediction of your theory is that if you radiate O2 and N2 with certain frequencies in the IR range, they will heat up. Yes, they will. We know that. You don't have to keep yelling. All this is known. If you use google you could probably find several lecture notes that go through this. They could probably also ask you to calculate the cross section for the direct quadrupole transition, for Raman, etc, etc. A slightly harder task- and one that I wouldn't be able to do in my head - is to calculate the spectral weight of the absorption line for the atmosphere. However, it can be done and if you had the proper training in physics you could possibly do that calculation yourself and hopefully it should agree with the textbook. If it doesn't agree, then I'd say there is a huge probability of error on your part. This is basic physics, yes it may be interesting to some people like yourself, but it is all very well known, I assure you. You would not be able to have a career doing quantum mechanics without knowing this stuff.
53Blair Macdonald Dr
Lee, theoretical physicist you claim you are; your tact in argument and is akin
to a creationist claiming the 'big bang' after the evidence for it has been
found. Oh, we knew that all along. You claim: 'I've already said that N2 and O2
absorb in the IR' but only after I set the pace, revealing QM modes, Raman
spectroscopy (which you seem to know nothing much about). Shame on you. What
would Galileo make of you? What would Professor Einstein indeed? Positivism!
The infrared catastrophe still stands. Good luck with your 1% (gases).
54Blair Macdonald No,
it is not common knowledge. Nobody combines 'IR' TE with Raman spectroscopy to
describe the greenhouse effect. If they did there'd be no debate. No issue. GH
theory relies on the premise the non GHGs do not emit or radiate. You've now
said they do.
55Tom Rodolfo Lee But
we did know this all along. It's in the textbooks and it's taught in quantum
mechanics classes. It was actually in one of my exams when I was an
undergraduate. Like I said, if you don't believe me either open a textbook on
quantum chemistry, or if ...See more

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56Blair Macdonald Do
you know something; it is possible to use Raman Spec to measure the Keeling
curve. Can you believe it; all based on the same principles and the Jet exhaust
experiment
57Blair Macdonald Raman
LIDAR; it measures the temperature of N2 and O2 in the lower thermosphere, to a
temperature of around 2500K Amazing! Raman Laser Spectroscopy is the instrument
of the 20th and 21th Century. IR the 19th
58Tom Rodolfo Lee Here
are some lecture notes on it: https://www.researchgate.net/file.PostFileLoader.html...
59Blair Macdonald Tom
Rodolfo Lee I will read this, and I will be searching for key words N2 O2 2338
1556 absorption bands in the IR atmosphere. I'll get back to you.
60Tom Rodolfo Lee I
suggest you have a read, calculate the quadrupole transition amplitudes - not
an easy task - and then try to calculate the spectral line for absorption of O2
and N2 in the atmosphere. People have already calculated/measured it and it
seems to be negligible. I could be wrong, it's not a trivial calculation, but
we know that it will be significantly smaller than CO2 and other heteronuclear
molecules because of the forbidden dipole transition. That's why O2 and N2 are
not greenhouse gases.
61Tom Rodolfo Lee If
you don't want to do the calculation yourself maybe just look at these other
lecture notes:
http://irina.eas.gatech.edu/EAS8803_Fall2009/Lec6.pdf...See more
http://irina.eas.gatech.edu/EAS8803_Fall2009/Lec6.pdf...See more
62Blair Macdonald Calculations
or not; this presents a paradox. N2 cannot absorb (or if it does, as you claim,
it is low) then why thermosphere, the CO2 laser, and why does it cool off at
solar eclipse totallity (where I started) if the air is a very poor conductor
of heat. How is it 'warm' and not radiate; nothing does that. Everything
radiates heat.
63Blair Macdonald Got
to go, late here, cheers. B
64Julian Ingham ^and
a good thing too, otherwise we'd be needing much stronger AC to deal with the
heating the earth would experience. Parity conservation, the unsung savior of
all life: Thanks parity conservation!
65Tom Rodolfo Lee I've
changed my mind. Blair is clearly a genius with a mind comparable to Einstein,
Planck and Boltzmann. Blair your revolutionary ideas need to be published. I
suggest writing a manuscript and sending it to Science magazine. Here is their
website:
http://www.sciencemag.org/aut.../science-information-authors
I am confident that your work will pass peer review, since you seem to be much more qualified than people who have earned doctorates and work professionally as researchers in quantum mechanics. After the publication of your groundbreaking research, I am sure you will be approached by several publishers to author a textbook on the basics of quantum mechanics, since all the current ones are wrong.
I wish you the best of luck.
http://www.sciencemag.org/aut.../science-information-authors
I am confident that your work will pass peer review, since you seem to be much more qualified than people who have earned doctorates and work professionally as researchers in quantum mechanics. After the publication of your groundbreaking research, I am sure you will be approached by several publishers to author a textbook on the basics of quantum mechanics, since all the current ones are wrong.
I wish you the best of luck.

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66Blair Macdonald Your
researchgate link. I reference this in my work, I don't think you have read it.
It totally destroys your rebuttal; is this all you have?Table 9.7 shows the
predicted QM wavenumbers of N2 and O2 (and doesn't mention Raman spectroscopy);
and pg 360 clearly describes and sets the stage of the IR paradox or
catastrophe and is in my introduction: "Homonuclear diatomic molecules
have no dipole allowed vibrational-rotational spectra. This
means they do not absorb or emit radiation on
transitions within the same electronic state. They
may have very weak quadrupole transitions.
Note:
The molecules N2 and O2, which represent the major
constituents of our atmosphere, cannot absorb the infrared
radiation emitted by the earth. Other molecules,
such as CO2, H2O, NH3 and CH4 do have an electric
dipole moment and absorb infrared radiation on their
numerous vibrational-rotational transitions. Although
they are present in our atmosphere only in small concentrations
they can seriously perturb the delicate energy
balance between absorbed incident sun radiation and
the energy radiated back into space by the earth (greenhouse
effect). If their concentration is increased by only
small amounts this can increase the temperature of the
atmosphere at the earth’s surface (greenhouse effect)"
means they do not absorb or emit radiation on
transitions within the same electronic state. They
may have very weak quadrupole transitions.
Note:
The molecules N2 and O2, which represent the major
constituents of our atmosphere, cannot absorb the infrared
radiation emitted by the earth. Other molecules,
such as CO2, H2O, NH3 and CH4 do have an electric
dipole moment and absorb infrared radiation on their
numerous vibrational-rotational transitions. Although
they are present in our atmosphere only in small concentrations
they can seriously perturb the delicate energy
balance between absorbed incident sun radiation and
the energy radiated back into space by the earth (greenhouse
effect). If their concentration is increased by only
small amounts this can increase the temperature of the
atmosphere at the earth’s surface (greenhouse effect)"
67Blair Macdonald Thank
you for your 'support', but I have a good eye for sarcasm when I see it; the
give away ' will pass peer review', no it will not. No one enjoys my theory
(theories) and discoveries; not the climate skeptics either (that's a good
thing). On 'a mind comparable to Einstein, Planck and Boltzmann': I was
thinking more like Kepler and Galileo as I feel like a heretic in this current
world. I do though have a theory that explains QM (wave particle duality,
etc..) with cosmological conjectures and observations. I can explain Hubble
expansion, accelerated 'dark energy' and inflationary expansion and more. My
theory matches observation and would unify and complete Albert Einsteins life
work. https://www.youtube.com/watch?v=NoTEwZ-pTtk It
also unifies QM to our reality: we are waves and we are 'particles, just a
posited by de Broglie. I have posited the economics demand curve is the de
Broglie wave function. I think we are finished here, you have helped me to
cover more of the 'traps' and you have offered some knew ones, that's good, but
like others you seem are stuck in the past defending the status quo. That is
not science: you might want to question whether you are really a scientist, and
what science is. How many times did Einstein shift his thinking with the new
'facts'. Hubble for one. And remember Alberts famous words: " it would
only take one". So far, with the atmosphere, I am not that
"one".

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68Blair Macdonald Tom
Rodolfo Lee, it's not finished, what does it leave us with? GHGs that 'hold up'
the thermal atmosphere - 1%!, and CO2 0.04%. Can you make a prediction, with
your law of heat trapping CO2; CO2 and temperature? So to speak, 'hot and spicy
CO2 adds no flavour in any other cake it's add to'. It's temperature benign -
everywhere (of course) other than the climate. It doesn't even factor in met.
weather theory. I did commercial pilot met theory, no CO2 there. Oh, on that,
do you know they are going to us Raman Laser on aircraft to detect high
altitude CAT - because it detects water movements. CO2 has no thermal utility:
there is not market for it, and animals and plants don't use it for its 'spicy'
properties. It doesn't factor in plate tectonics where it is sub ducted in
extremely high temperature and concentrations (water does); Snow pack avalanche
stability, it is there x10 more than in the air, it does not factor and is not
measured, IT SHOULD BE, lives would depend on it and this knowledge;
respiration: the nose has evolved to moderate temperature in all mammals; it's
water, and not CO2 that 'traps the heat'. You are no more than a snake
salesman.You are party to selling a story, a myth, superstition, exploiting
CO2's properties, and now its thermoelectric properties - of a invisible gas;
Dr Lee, that is fraud. You should call it the Jesus or god gas, or just the
magic gas.
For you to succeed in convincing the world that O2 and N2 are as important as CO2 and methane in regards to being greenhouse gases, you will have to do the calculations as the physicist told you to or else set up an experiment of your own to show the numbers.
ReplyDeleteBy the way I agree with you that Water is the dominant GHG and that AGW is a giant hoax.
ReplyDelete